[Yellow Mustang Girl]

Please post all homework-related questions on this thread.

This thread is for getting help when get stuck with researching for an essay, solving a math problem, finding the capital of a country...etc. Basically, the thread is for questions where you are only looking for the right answer or a few responses at the most. If you are looking for a wide variety of input, such as getting as many responses as possible for a survey or asking for general ideas for starting a project, you are welcome to start a new thread on it.


From the previous thread:

Originally Posted by SilviahPaulian (View Post) Anyone willing to translate that for me? Guess it's French.Sorry. I'm Brazilian and i have no clue. http://www.desafionacional.com.br/dn...526d58juyh.mp3 ...

[Michelle Dessler]

Lemurian, thanks so much for answering my question on the previous thread!

[valé.]

SilviahPaulian : Yes, it is french :

"le petit déjeuner" = breakfast

"fenêtre" = window

"clé" = key

This is the translation

[ellen-cheerleaderx]

OMG thanks so much for this thread
wait until september, i'm gonna ambush you with my french homework LOL

[valé.]

Originally Posted by ellen-cheerleaderx (View Post) OMG thanks so much for this thread wait until september, i'm gonna ambush you with my french homework LOL

I'll be happy to be ambushed with your french homework

[GalindaIsPopular]

LOL!!! French is pretty hard!

[valé.]

Originally Posted by GalindaIsPopular (View Post) LOL!!! French is pretty hard!

I agree with you That's why I'll be here to help if someone needs me

[Snøball]

Anyone from Britain who can tell me what it means to be British for young people today? This is for a oral exam, so please hurry!

[Caroo]

Is there anyone good in math? i have an exam tomorrow, and I'd call one of my friends but they don't get this exercise either

There are two machines, Machine X and Machine Y, and they both produce Keys. Machine X produces 60% of the keys and Machine Y produces 40%
2% of all the key's produces by Machine X can't be used and
0,9% of all the key's produced by Machine Y can't be used.

At the and of the day, the boss picks 5 keys randomly

- What's the chance they can all be used
- What's the chance only one of them can be used
- What's the chance one or more can be used

Please? I'd be grateful for the rest of my life because I can't fail this exam.

[SharTheLove]

I have to do some hw soon.

[mcgoslinginlove]

Originally Posted by Caroo (View Post) Is there anyone good in math? i have an exam tomorrow, and I'd call one of my friends but they don't get this exercise either There are two machines, Machine X and Machine Y, and they both produce Keys. Machine X produces 60% of the keys and Machine Y produces 40% 2% of all the key's produces by Machine X can't be used and 0,9% of all the key's produced by Machine Y can't be used. At the and of the day, the boss picks 5 keys randomly - What's the chance they can all be used - What's the chance only one of them can be used - What's the chance one or more can be used Please? I'd be grateful for the rest of my life because I can't fail this exam.

ok well if i've done my math correctly there's a 99.98% chance that they can all be used although I wouldn't quote me on that This is reallycomplicated and I think I might be doing something wrong. I can't figure it out. what Math course is this? I'll ask my step mom if she's here, She's a math major.

[Caroo]

Originally Posted by mcgoslinginlove (View Post) ok well if i've done my math correctly there's a 99.98% chance that they can all be used although I wouldn't quote me on that This is reallycomplicated and I think I might be doing something wrong. I can't figure it out. what Math course is this? I'll ask my step mom if she's here, She's a math major.

Well, I finally understand it after a lot of hours and some help from a friend, so this is how it's done

- 2% of 60% is (2/100)x(60/100)=120/10000=1,2%
- 0,9% of 40% is (0,9/100)x(40/100)=36/10000=0,36%
so in total the (1,2%+0,36%)=1,56% of the keys can't be used.

- What's the chance they can all be used?
The joint probability of a series of events is P=P(E1) x P(E2)...x P(En)
In this case on 5 events the probability is (100% - 1,56%) x (100% - 1,56%) x (100% - 1,56%) x (100% - 1,56%) x (100% - 1,56%) = 92,44%

- What's the chance only one of them can be used?
It's the joint probability of "one can be used" and "4 can't be used" so:
(100% - 1,56%) x 1,56% x 1,56% x 1,56% x 1,56% => (5,83 e-8 )^5

- What's the chance one or more can be used?
It's 100% -the chanche that all of them can't be used so:
100%- [(1,56%)x(1,56%)x(1,56%)x(1,56%)x(1,56%)]=100% - 9,239e-10= almost 1...



Thank you anyway

[mcgoslinginlove]

ha ok see me and my friend were doing it way different but i get it. Thank god i dont have to take math anymore.

[Caroo]

i have it 6 hours a week and unfortunately no choice to drop it

[natalie8you]

Originally Posted by Caroo (View Post) i have it 6 hours a week and unfortunately no choice to drop it

I have Calculus next year...and I'm not looking forward to it.
Not a fan of math.